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--- courses:phy101l:6 [2023/12/01 04:39] – asad
+++ courses:phy101l:6 [2023/12/07 05:51] (current) – asad
@@ Line 6: / Line 6: @@
 $$ H = \frac{k A \Delta T}{L} $$
-where $k$ is **thermal conductivity** which has the units [W m^{-1} K$^{-1}$], $A$ is the cross-sectional area of the conductor, $L$ is its length and $\Delta T$ is the difference in temperature between the two ends of the conductor.
+where $k$ is **thermal conductivity** which has the units [W m$^{-1}$ K$^{-1}$], $A$ is the cross-sectional area of the conductor, $L$ is its length and $\Delta T$ is the difference in temperature between the two ends of the conductor.
+The thermal conductivity of copper and steel are given below.
+^ Material ^ Thermal conductivity [W m$^{-1}$ K$^{-1}$] ^
+| Copper (Cu) | $401$ |
+| Steel (Fe+C) | $14$ |
 ===== - Method and data =====
+==== - List of apparatus ====
+  - Beaker
+  - Thermometer
+  - Substance (Copper, Steel)
+  - Weighing scale
+  - Water (20 ml)
+==== - Setup and Procedure ====
 Using a Vernier calipers measure the radius of the rods and from the radius ($r$) calculate $A=\pi r^2$.
 Using a thread and a meter scale measure the length $L$ of the rods.
+==== - Data table ====
 Measure the temperature changes and note down in the following table.
-^ Time [min] ^ Copper $T$ ^ Steel $T$ ^
+^ Time [minute] ^ Temperature of Copper [$^\circ$C] ^ Temperature of Steel [$^\circ$C] ^
 | 0 |  |  |
 | 1 |  |  |
@@ Line 27: / Line 43: @@
 ===== - Heat transfer =====
+Compare $H_c$ and $H_s$ in units of J min$^{-1}$.
 ===== - Discussion and conclusion =====