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courses:phy101l:4 [2023/07/25 03:45] – [2. Method and data] asadcourses:phy101l:4 [2023/11/05 02:37] (current) – [1. Introduction] asad
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 ====== 4. Spring constant from extension and period ====== ====== 4. Spring constant from extension and period ======
 [[https://colab.research.google.com/drive/1tD3YzjG3QRVFyrV-L1ccF84yx7QW4eYf?usp=sharing|Google Colab example]] [[https://colab.research.google.com/drive/1tD3YzjG3QRVFyrV-L1ccF84yx7QW4eYf?usp=sharing|Google Colab example]]
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 ===== - Introduction ===== ===== - Introduction =====
 +Spring constant is a property of a spring; its value $k$ should be a constant. You will calculate $k$ using two different methods: first, using the extension $l$ caused by a hanging mass $m$ and second, using the period $T$ for a given hanging mass $m$.
 +
 +{{:courses:phy101l:spring.png?nolink|}}
 +
 +When a mass $m$ is hung from an unstretched spring, it is extended by a length $x=l$ because of the gravitational pull of the earth on the mass. The spring exerts a restoring force $F$ on the mass opposite to its gravitational force $mg$. According to Hooke's law
 +
 +$$ F \propto -l \Rightarrow F = -kl $$
 +
 +where $k$ is the spring constant. Replacing $F=-mg$ we get $-mg = -kl $ and
 +
 +$$ k = g\frac{m}{l}. $$
 +
 +$$ l = \frac{g}{k}m + 0 $$
 +
 +For the second method, you will use the relation between period and mass
 +
 +$$ T = 2\pi \sqrt{\frac{m}{k'}} $$
 +
 +which leads to 
 +
 +$$ k' = 4\pi^2 \frac{m}{T^2}. $$
 +
 +$$ T^2 = \frac{4\pi^2}{k'} m + 0 $$
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 +The values $k$ and $k'$ should be very similar because they are both the spring constant of the same spring.
  
 ===== - Method and data ===== ===== - Method and data =====
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 ===== - Discussion and conclusion ===== ===== - Discussion and conclusion =====
 +  - Why are $k$ and $k'$ different? 
 +  - Which one is greater, $\delta k$ or $\delta k'$? Why? 
 +  - In which method we have higher fitting error?
courses/phy101l/4.1690278320.txt.gz · Last modified: 2023/07/25 03:45 by asad

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