Google Colab

$$ mgh = \frac{1}{2} m r^2 \omega^2 + \frac{1}{2} I \omega^2 + n_1 W $$

$$ \frac{1}{2} I \omega^2 = n_2 W \Rightarrow W = \frac{I\omega^2}{2n_2} $$

$$ I = \frac{2mgh - mr^2\omega^2}{\omega^2\left(1+\frac{n_1}{n_2}\right)} $$

$$ \frac{\omega+0}{2} = \frac{2\pi n_2}{t} \Rightarrow \omega = \frac{4\pi n_2}{t} $$

$$ h = 2\pi r n_1 $$

1. Why does the flywheel come to a stop?
2. Why are the 4 measurements of moment of inertia different?
3. When does the flywheel reach its maximum velocity?
4. What does the standard deviation (numpy.std) of $I$ tell you?