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un:vector-field [2024/10/11 05:04] asadun:vector-field [2024/10/11 08:44] (current) asad
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 In the image above, the divergence of the vector field (arrow) $e^{-(x^2+y^2)}(1-2x^2)$ mentioned in the first section is shown in color. In the image above, the divergence of the vector field (arrow) $e^{-(x^2+y^2)}(1-2x^2)$ mentioned in the first section is shown in color.
  
-===== - Carl =====+===== - Curl =====
  
 Curl refers to the circulation of a vector field, i.e. how much circular motion there is in that field. Anywhere in the two-dimensional field, if the vectors below a circular area have less magnitude than the vectors above, a clockwise rotation will occur, and the curl will be negative in this case. Curl is positive if the rotation is counterclockwise. The mathematical form of the curl is: Curl refers to the circulation of a vector field, i.e. how much circular motion there is in that field. Anywhere in the two-dimensional field, if the vectors below a circular area have less magnitude than the vectors above, a clockwise rotation will occur, and the curl will be negative in this case. Curl is positive if the rotation is counterclockwise. The mathematical form of the curl is:
  
-$$ \nabla\times \mathbf{F} = \left(\frac{\partial F_z}{\partial F_y}-\frac{F_y}{F_z}\right) \hat{i} + \left(\frac {\partial F_x}{\partial F_z}-\frac{F_z}{F_x}\right) \hat{j} + \left(\frac{\partial F_y}{\partial F_x}-\frac{F_x}{ F_y}\right) \hat{k} $$+$$ \nabla\times \mathbf{F} = \left(\frac{\partial F_z}{\partial F_y}-\frac{\partial F_y}{\partial F_z}\right) \hat{i} + \left(\frac{\partial F_x}{\partial F_z}-\frac{\partial F_z}{\partial F_x}\right) \hat{j} + \left(\frac{\partial F_y}{\partial F_x}-\frac{\partial F_x}{\partial F_y}\right) \hat{k} $$
  
 {{:bn:un:curl.png?nolink|}} {{:bn:un:curl.png?nolink|}}
  
 In the image above, the $z$-component $e^{-(x^2+y^2)}2xy$ of the curl of the vector field (arrow) mentioned in the first section is shown in color. The curl is a vector quantity, but since the field is two-dimensional here, the x and y components of the curl will be zero. In the image above, the $z$-component $e^{-(x^2+y^2)}2xy$ of the curl of the vector field (arrow) mentioned in the first section is shown in color. The curl is a vector quantity, but since the field is two-dimensional here, the x and y components of the curl will be zero.
un/vector-field.1728644695.txt.gz · Last modified: 2024/10/11 05:04 by asad

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