To understand the internal structure of a planet or moon, we need to relate its mass ($M$) and moment of inertia ($I$) to the size and density of internal layers. These properties can also be inferred from gravitational field measurements, specifically using the coefficients $J_2$ and the dimensionless parameter $\Lambda$.
Assume the planet/moon has:
We assume constant density in each layer.
The mass of the object is the sum of the masses of its spherical layers:
$$ M = \frac{4\pi}{3} \left[ \rho_c R_c^3 + \rho_m (R_m^3 - R_c^3) + \rho_i (R_g^3 - R_m^3) \right] \tag{1} $$
This equation connects the mass $M$ to the layer boundaries $R_c$ and $R_m$.
Each spherical shell contributes to the moment of inertia. The total moment of inertia is:
$$ I = \frac{8\pi}{15} \left[ \rho_c R_c^5 + \rho_m (R_m^5 - R_c^5) + \rho_i (R_g^5 - R_m^5) \right] \tag{2} $$
These two equations (1) and (2) form a solvable system for the unknown radii $R_c$ and $R_m$.
In practice, we don’t always know $I$ directly. However, we can estimate it using measurements of:
The gravitational flattening $J_2$ is related to the difference in moments of inertia around the polar and equatorial axes:
$$ J_2 = \frac{I_p - I_e}{M R_g^2} \tag{3} $$
The parameter $\Lambda$ is defined as:
$$ \Lambda = \frac{\omega^2 R_g^3}{G M} \tag{4} $$
Where:
Using these, the moment of inertia factor $\frac{I}{M R_g^2}$ can be approximated by:
$$ \frac{I}{M R_g^2} \simeq \frac{\frac{2}{3} J_2}{J_2 + \frac{1}{3} \Lambda} \tag{5} $$
This equation provides a practical way to infer $I$ from observable quantities, even without directly measuring internal mass distribution.
| Quantity | Equation | Description |
|---|---|---|
| Mass from interior model | $M = \frac{4\pi}{3} [\dots]$ | Adds up volume × density of layers |
| Moment of inertia from model | $I = \frac{8\pi}{15} [\dots]$ | Integrates $r^2$ weighted mass for each layer |
| $J_2$ | $J_2 = \frac{I_p - I_e}{M R_g^2}$ | Measures deviation from spherical symmetry |
| $\Lambda$ | $\Lambda = \frac{\omega^2 R_g^3}{G M}$ | Measures centrifugal force’s effect |
| $I$ from $J_2$ and $\Lambda$ | $\frac{I}{M R_g^2} \simeq \frac{\frac{2}{3} J_2}{J_2 + \frac{1}{3} \Lambda}$ | Useful approximation to get $I$ from observations |
By combining gravitational field measurements and simple physical models, we can infer the internal structure of distant planetary bodies—even when we can’t look inside them.